穆罕默德-本-拉希-德阿勒马克图姆
范文一：南岗二模
2014年南岗二模
一、单项选择(本题共20分，每小题1分)
() 1. Boys and girls, please remember, the more you learn, the more ______ you can go to a better
senor high school.
A. easier B. easy C. easily () 2. Nowadays, some parents would like their children to learn in ____ one–to–one situation, for
they think their children can get the full attention of the teacher by doing that.
A. an B. a C. /
() 3. - If there are _____ people driving, there will be ____air pollution.
- Yes, then the air will be fresher.
A. less; less B. fewer; less C. fewer; fewer () 4. - Where is Mr. Green?
- He _____ three days ago, and he’ll be back next Sunday.
A. has been away B. has gone away C. left away () 5. - _____ fine weather! Let’s go to the park, shall we?
- Good idea!
A. How B. What a C. What () 6. - What are on show in the museum, Lucy?
- Some photos _____ by the children of Taiwan.
A. have been taken B. were taken C. taken () 7. - Have you found the information about the famous people ___ you can use for your
composition?
- Not yet. I’ll search some on the Internet.
A. who B. whom C. which () 8. - My computer doesn’t work. Could you help me, Jim?
- Certainly! Let me have a look. ______ must be something wrong with the CPU.
A. There B. That C. It () 9. On Mother’s Day of 2014, our English teacher Miss Li ______ each of us to write a letter to
our mothers in order to show our best love and appreciate their ______ meticulous(精心
的)care for us.
A. suggested, 15 years’ B. advised, 15-year C. encouraged, 15–years
() 10. - Hi, Jim! Could you tell me ______!
- Skiing! I think it’s exciting!
A. which sport do you like best
B. what is your favorite sport
C. whether you like sports or not
() 11. - Who is the man over there? Is it Mr. Li?
- No, it ____ be him. Mr. Li is much taller.
A. mustn’t B. may not C. can’t
() 12. - Could you tell me your secret of learning Chinese?
- Yes, _____ the teacher’s help, I can’t get such great progress (进步).
A. with B. under C. without
13. - _____ will you return from your holiday?
- In two weeks.
A. How soon B. How often C. How long
14. - Would you mind my opening the widow?
- _____. We need some fresh air.
A. Certainly B. You’d better not C. Of course not
15. We should develop the good habit of saving time. Today’s hard work is the _____ of
tomorrow’s harvest(收获). If you waste time today, you will regret tomorrow.
A. result B. cause C. excuse
16. My uncle isn’t used to living in Canada because he can speak _____ English _____ French.
And he thinks it’s hard for him to communicate with the Canadians around.
A. both, and B. neither, nor C. either, or
17. In some western countries, when people visit sick friends, people only express the feeling or
wishes instead of telling patients what to do. Patients also show their thanks. Therefore, which
situation fits western custom?
a: I am sorry to hear you have a bad cold, drink more water. Good health. A.
b: Thanks, I will do what you say.
a: I am really sorry to hear you break your leg, take care, I hope you will be better soon. B.
b: Thank you for your kindness.
a: I feel sad to hear you are ill. I hope you can be well soon.
C.
b: It is none of your business.
() 18. People know the dangers of fires. It is good for a family to learn how to prepare for fire.
What should we do order to keep safe?
(1) Put a smoke alarm (报警器) in the house. The sound can tell everyone to leave the house at
once.
(2) Make escape plans. If there is a fire, everyone follows the plan to get out. (3) Open the hot door when the house is on fire so that the fire can grow more quickly. (4) Stay close to the floor! Fire can be more dangerous than smoke.
(5) Buy fire extinguishers (灭火器) in the house. Everyone in the family should know how to use
them.
A. (1) (2) (5) B. (1) (3) (4) C. (2) (3) (5)
() 19. Different kinds of calling time were served Basic Cost Calling Time
according to different basic costs. But 0.1yuan Pack A 5yuan 60 minutes a minute need to be paid for extra calling time, Pack B 10yuan 120 minutes
no matter which pack (套餐) it is. Pack C 15yuan 170 minutes If Susan needs two and a half hour’s call every month, 表格见纸稿
________ is the best choice for her.
A. Pack A B. Pack B C. Pack C
() 20. Which stress of the following words is different from the other two?
A. Pardon. B. Absent. C. Balloon.
二、完形填空(本题共10 分，每小题1分)
Tomas Edison succeeded after trying nearly 2000 times to find one material to make light bulb(灯泡)more perfect. When Edison was ___21___ about that, he said” I didn’t fail. I just
found out 2000 ways how not to make it work.”
As students, we take exams very often. Sometimes we think we have tried our best to do that, but finally we failed to get high_22___. When we play games, we might be beaten by others. We have to accept these _23__ facts. It seems that all the failures happen naturally and almost__24___ of us has had such experiences. In fact, failure isn’t a stranger to our daily life.
It is always hiding near us and ready to beat us. But do you know the secret to overcome failure? Let me tell you, it__25_ our attitude.
There are different attitudes towards failure. Some people _26_ when they fail; they think the word is at its end. Once they fail. They can not face any challenge any more, they just believe they will never achieve success. However, others who have a different attitude towards failure___27__ take it seriously and just let it be. Through deep thought, they learn much from a failure and see the light of hope. They always __28___ failure as valuable experience.
The road in front of us won’t be even(平坦的), so difficulty cannot be avoided, failure
cannot be avoided, _29_. In fact, what really matters is not failure itself, but what we do with it. Dear students! Don’t be afraid of failure, it is not a bad thing at all. It proves you are ___30___the way to success. Remember the proverb(谚语): Where there is a will, there is a
way.
根据短文内容选择最佳答案。
() 21. A. ask B. asking C. asked
() 22. A. abilities B. scores C. cultures
() 23. A. sad B. pleasant C. surprised
() 24. A. everyone B. every one C. no one
() 25. A. deals with B. focus on C. depends on
() 26.A. have confidence B. are confident C. lose heart
() 27. A. always B. don’t C. aren’t
() 28. A. think over B. think about C. think of
() 29. A. too B. also C. either
() 30. A. in B. on C. by
三、阅读理解(本题共20分，每小题1分)
(A)
A great big man, weighing about 250 pounds, walked with slow heavy noisy footsteps up to the produce counter (柜台) in the supermarket. “Give me half a head of cabbage,” he told the
clerk(店员).
“All we have are whole heads,” the clerk replied in a cold voice.
“I don’t want a whole head,” the custom answered, “Just half a head. Are you going to sell me
half a head?”
“Wait a minute,”said the clerk nervously, “Let me ask the manager.”
She went back where the manager was. “Hey,” she said to the manager, “there’s a big, stupid, looking buffalo(水牛) out front, he wants me to sell him half a head of cabbage. Shall I tell the
fool to…” Suddenly, she noticed the manager staring — not at her. Turning, surprisingly, the clerk saw that ______.
Quickly, the clerk turned back to the manager, “And this gentleman (绅士) ,” she said, “wants
to buy the other half.”
根据短文内容选择最佳答案。
() 31. The underlined word “staring” in the passage most probably means ______.
A. talking B. looking C. asking
() 32. The big man came to the produce counter in the supermarket _____.
A. in a quiet way B. in a hurry C. slowly nut nosily () 33. The clerk didn’t sell cabbage to the big man because ______.
A. he asked for half a head of cabbage
B. he was too stupid
C. he wanted to buy so much that she didn’t have enough
() 34. Which of the following sentences is TRUE?
A. When talking to the manager, the clerk was referring to(指的是) two different customers.
B. The customer was a tall and fat woman.
C. In fact, there were three people in the passage. () 35. “______” can be the missing sentences in the passage.
A. the big and tall customer had followed her and heard every word
B. the big and tall customer was far away from her
C. the big and tall customer was smiling happily to her
(B)
Item 图片见纸稿 图片见纸稿 图片见纸稿 图片见纸稿
Basketball Soccer Volleyball Table Tennis
First Played 1891 300B.C. 1895 1900
Coming from America China America England
The number of 5 players 11 players 6 players 1 or 2 players
the players in
each team(on
court)
Playing Time Forty-eight One and a half No time limit(不No time limit
minutes(4 parts) hours(2 parts) 限时)
Famous Sports NBA FIFA World Cup FIVB WTTC
Event
Word Box: on court 上场
根据表格所提供的信息选择最佳答案。
() 36. All the games in the table were first played before the nineteenth century except _____.
A. basketball B. soccer C. table tennis () 37. ______ played soccer earliest in the world.
A. Americans B. Chinese C. Englishmen
() 38. People can find _____ players playing on court in a volleyball match.
A. six B. eleven C. twelve
() 39. Every part of the basketball playing time is about ______.
A. 12 minutes B. 24 minutes C. 45 minutes
() 40. Which of the following is TRUE according to the information above?
A. NBA is a famous sports event which is about baseball.
B. Both volleyball and table tennis come from Europe.
C. It is over 2000 years since people began to play soccer.
(C)
There is always something that we can never forget. And it can really change our life. Time is important for everyone. It organizes our everyday moments. However, time never had any importance in my life until I received a watch from my father. It organized my life and made me more responsible (有责任心的). The watch is round in the center with two silver bands (带)
that go around my wrist (手腕) and all of it is made of silver.
I received this gift on a Sunday. That day I had to go to the airport at 9:00 a.m. to pick up Uncle Jim and take him to my father’s house. However, I was late because I went to play with my
friends. Later on that day, around 11:00 a.m., I remembered my uncle and went to the airport to meet him. Half an hour later, I got to the airport, but I was too late. He had left the airport and taken a taxi to my father’s house.
I got to my father’s house at 2:00 p.m. that day. Looking at my father’s face, I felt ashamed at
that moment. My father asked me to sit next to him and he handed me this watch as a gift. Then he said, “Bob, did you have fun with your friends today?” “Yes, Father, and I’m sorry about not
picking up Uncle Jim," I replied. He then said, "What you did was not very nice and you should be sorry for your actions. I think you should learn something from it, and this watch will be a reminder (勾起回忆的东西) for you in your future life.” The watch is very important to me, not
because of its price, but because of the lesson that I learned from it.
Today I still remember my father’s words“Respect time and never be late for anything.”
根据短文内容判断正、误。
(注意:考生将答题卡相应位置涂黑。正确的涂“A”，错误的涂“B”)
() 41. The watch given by Bob’s father is round in the center which was made of silver.
() 42. Bob arrived at the airport 2 hours later than the appointed (约定的) time.
() 43.Bob missed meeting his aunt at the airport because he and fun with his friends. () 44. Bob thinks the watch is very important because it is expensive.
() 45. Bob’s father gave him the watch in order to tell him to respect time.
(D)
A sunflower is a sunflower. A mobile phone is a mobile phone. But can you (联合) the two to
do something for you local environment? As early as next year it may well be possible. As we all know, mobile phone is developing so quickly, over 650 million mobile phones have been sold this year. Most of them will be thrown away in two years, adding plastics, heavy metal or chemical waste to the environment. This means producers (生产商) have to find ways of
recycling them. Luckily, a biodegradable (生物所能分解的) material was, this month, invented
and used to make mobile phones by scientists. When you have finished with your mobile phone next time, you can be able to bury it in the garden or a plant pot and wait for it to flower.
It looks like any other plastic, but some days later, it can break down (分解) into the soil and
form nitrates (硝酸盐). It will never give out any harmful chemicals waste. The nitrates can feed the seed and help the flower grow. So you don’t have to worry about the phone when you have
finished using it. It hoped that the new type of mobile phones will encourage people to recycle. “We’ve only put sunflower seeds into the mobile phones so far. But we are trying to find out which flowers would perform(表现) best. Maybe we could put roses into the mobile phones next time.”said the leader of the research team, who is working at the University of Warwick in Britain.
根据短文内容选择最佳答案。
() 46. Now people deal with most of the used mobile phones by _______.
A. throwing them away B. turning them into nitrates C. recycling them () 47. The underlined word “bury” in the passage means “_______” in Chinese.
A. 燃烧 B. 埋葬 C. 砸碎
() 48. Picture ______ shows how a biodegradable mobile phone works.
图片见纸稿 图片见纸稿 图片见纸稿
A. B. C.
() 49. Which of the following is TRUE according to the passage?
A. Over 650 million mobile phones will be phone works.
B. Only sunflowers can be grown this way in the future.
C. Scientists use a biodegradable material to make mobile phones in order to deal with some
environment problems.
() 50. The main idea of the passage is about ______.
A. mobile phone is developing
B. mobile phones can never be grown
C. mobile phones and the environment
第?卷
四、任务性阅读(本题共10分，每空1分)
先阅读(A)、(,)两篇短文，然后根据题目要求及所给语境完成下列四项任务。
(,)
full three teenager real bad
You may know about “junk food” like French fries. But do you know about “junk sleep”?
Recently, a British survey found that electronic(电子的) products in _51__ bedrooms are
affecting their sleep. Almost a quarter of the kids said they __52__ asleep more than once a
week while watching TV, listening to music or using other electronic products. “We’re __53__
worried about this situation.” said a British expert. “Junk sleep means the quality(质量) of the
sleep is bad. If you don’t get good rest, you don’t work well in school the next day.” The
survey found that 40 percent of the kids felt tired each day. Among them, girls between 13 and
16 feeling __54__. Nearly all the teenagers have a phone, Mp4 or TV in their bedroom. And
around two __55__ of them have all three. Parents must help keep their children away from
“junk sleep”.
(B)
How to deal with the relationship between boys and girls well? It is easy. You should keep a normal and healthy state of mind. Our schools and classes are made up of boys and girls. It is very natural for students to make friends with each other. However, you should keep in touch with the other sex(性别) in public instead of in secret. Don’t be too nervous or too shy. You
can make friends with the students who have the same interest as you. You’d better not fall
into early love. The schoolboys or schoolgirls are at a special age of being rich in so called emotion. They often regard the friendship as a sign of love. They fall in love at an early age easily. Actually, boys and girls at middle school are too young to carry the heavy duty of love. 任务1:用方框里所给单词的适当形式填空，使文章通顺、连贯、合理(每词限用一次)
51.______ 52.______ 53.______ 54._______ 55.________
任务2:根据英文释义及首字母提示，拼写单词。
56. a__________: usual, not special
57. e__________: the feeling such as love, hate, jealousy
任务,:同义词转换，每空一词。
Actually, boys and girls at middle school are too young to carry the heavy duty of love.
Actually, boys and girls at middle school aren’t __58__ ___59___ to carry the heavy duty
of love.
任务,:根据短文内容简答问题。
What do the school boys and school girls often regard the friendship as?
60._______________________________________
五、交际应用(本题15分，每空1分)
(A) 从A-J选项中选出能填入空白处的最佳选项补全对话。(选项中有两项是多余的)
A: Excuse me, sir. ___61___
B: Yes. What can I do for you, young man?
A: __62__ Some of my classmates want to go to Beijing for a short visit.
B: Good idea. Beijing is an old city that is well worth visiting.
A: So I’d like to look for some information about traveling. ___63___
B: We certainly do. There are quite many such tours. ___64___
A: Well, we’re going to visit some famous places such as the Great Wall, the Summer Palace and
so on.
B: They are all places of great interest in Beijing. ___65___
A: Well, today is June 24. And we still have three more days before finishing the final exam.
___66___
B: Oh, I see. There are two kinds of ways of tours: by plane and by train. Which will you
choose?
A: __67__ It is much faster.
B: All right. __68__ It will help you.
A: Thank you very much.
B: You’re welcome.
61.________ 62.________ 63.________ 64.________
65.________ 66.________ 67.________ 68.________
A. We’ll be free time the day after that. B. Here’s the information about the tour. C. When are you going to take the tour? D. Could you give me some help? E. What places are you going to visit? F. I’ll finish my school next month. G. We are going to fly there. H. I want to take the train to Beijing. I. Can I help you? J. Do you have four day’s tours? K.
(B) 填入一个适当的词补全对话，每空一词。
,: Hello. May I __69___ to Bill? This is Mary!
B: Hello. This is Bill!
A: Bill, __70__ been invited to dinner tonight. What time should I arrive for that? B: Did they tell you __71__ the dinner would begin?
A: Yes, they said the dinner would begin at seven.
B: Then get there before 7:00. But make sure you are not much earlier __72__ the time you make. A: Why?
B: Maybe they are still __73__ ready for the dinner.
A: What should I take?
B: For the first time, you can bring a small present. It is polite__74__ you to do that. A: I have got it. Thank you for your help.
B: That’s all right. Enjoy __75__ at the party.
69.______ 70._______ 71.________ 72._________
73.______ 74._______ 75.________
六、阅读表达(本题共10分)
(A) 阅读短文，根据短文内容完成表格，每空一词(本题共5分，每空,分)
Dubai (迪拜) is a city of big business, expensive hotels, and shopping malls. It lies in the south of the Arabian Peninsula (阿拉伯半岛). As it is a desert city, there is no doubt that Dubai is extremely hot and dry, and most days are sunny, with an average(平均的) temperature around
40? all the year round. If you like, you can also climb the highest building like Tom Cruise in Mission Impossible 4. In fact, Dubai itself is an impossible mission, but people living there made
thit. In the early 20 century, Dubai was not a successful trading port(港口), most people lived as
fishermen. Then after oil was discovered, Dubai began to change. Today it is one of the world’s
business centers. Dubai has an amazing mix of population. Till now, the foreign people from 150 countries have been attracted and lived, worked in Dubai, most of them welcome the city’s growth.
But quite a few Dubai natives worry about the speed of change. As a Dubai native says, “We must
always remember it is our own hometown, we can make it more beautiful by ourselves and there’s
still a lot more work to do.”
Location(位置) In the __77__ part of
Arabian Peninsula
___78___ Hot and dry, with an average Dubai— one temperature around 40? all the of the __76___ year around business center
___79___ from 150 countries
Population Dubai’s natives Worrying about the
speed of __80___
76._______ 77.______ 78._______ 79.______ 80._______
(B) 根据所给中英文信息完成应用文。(本题共,分)
假如你是学生会的Mike，请你以学生会的名义给九年级全体学生写一份报告，并提醒大
家携带雨伞。要求包含所有信息，至少写出,句话。
What to do Go camping
When to meet 7:00 a.m.
Where to meet No.3 Bus Stop in front of the School Gate
What to wear Sports shoes
All the students in ______ Nine,
The Students' Union will hold an activity this Sunday. __________________
________________________________________________________________ ________________________________________________________________ ________________________________________________________________ ________________________________________________________________
The Students’ Union
th May 10
七、书面表达(本题共15分)
同学们，在业余时间里，你们都干什么呢,是遨游书海，增长知识,还是锻炼身体，
增强体质,抑或是听听音乐，陶冶情操……下面请你围绕“中学生如何有效地
(efficiently)利用业余时间”这一话题，展开思路谈谈你的感想。
要求:1. 请根据所提供的信息材料和话题(不要逐句翻译)，写出结构严谨、内容完整、
语言丰富优美、语法准确无准确、可读性强的短文。
2. 至少80词。
3. 不得使用真实姓名，地名和学校名。
4(题目自拟。
2014年南岗区调研测试(二)
英语学科参考答案及评分标准
一、1-5 CBBCC 6-10 CCABB 11-15 CCACB 16-20 BBABC
二、21-25 CBABC 26-30 CBCCB
三、31-35 BCACA 36-40 CBCAC 41-45 ABBBA 46-50 ABCCC
四、51. teenagers’ 52. fell 53. really 54. worst 55. thirds
56. normal 57. emotion 58. old 59. enough 60. A sign of love. 五、(A) 61-68 DFJECAGB
(B) 69. speak 70. I’ve 71. when 72. than 73. getting 74. of 75. yourself 六、76. world’s 77. southern 78. Climate 79. Foreigners 80. change
范文二：南岗二模、、、、
∴
,故正确; B 、∵
, ,
∴ ,故错误; C 、∵ DF ∥ AC ,
∴
,故错误; D 、∵
, ,
∴ =.故错误. 故选 A .
【点评】 此题考查了相似三角形的判定与性质以及平行线分线段成比例定理.注意掌握各线段的对 应关系是解此题的关键.
9. 如图, 将 △ ABC 绕点 A 按逆时针方向旋转 40°到 △ AB ′ C ′ 的位置, 连接 CC ′ , 若 CC ′ ∥ AB , 则∠ BAC 的大小是( )
A . 55° B . 60° C . 65° D . 70°
【考点】 旋转的性质.
【分析】 根据旋转的性质得 AC=AC′ ,∠ CAC ′ 等于旋转角,然后利用等腰三角形的性质和三角形内 角和计算出∠ C'CA 的度数,再由平行线的性质即可得到∠ BAC 的大小.
【解答】 解:∵△ ABC 绕点 A 按逆时针方向旋转 40°到 △ AB ′ C ′ 的位置,
∴ AC=AC′ ,∠ CAC ′ =40°,
∴∠ AC ′ C=∠ ACC ′ =70°,
∵ CC ′ ∥ AB ,
∴∠ BAC=∠ ACC ′ =70°,
故选 D .
【点评】 本题考查了旋转的性质:对应点到旋转中心的距离相等;对应点与旋转中心所连线段的夹 角等于旋转角;旋转前、后的图形全等.
10.已知 A , B 两地相距 4千米,上午 8:00,甲从 A 地出发步行到 B 地,上午 8:20乙从 B 地出 发骑自行车到 A 地, 甲, 乙两人离 A 地的距离 (千米) 与甲所用的时间 (分) 之间的关系如图所示, 由图中的信息可知,乙到达 A 地的时间为( )
A .上午 8:30 B .上午 8:35 C .上午 8:40 D .上午 8:45
【考点】 函数的图象.
【专题】 压轴题.
【分析】 根据甲 60分走完全程 4千米,求出甲的速度,再由图中两图象的交点可知,两人在走了 2千米时相遇,从而可求出甲此时用了 0.5小时,则乙用了(0.5﹣ )小时,所以乙的速度为:2÷, 求出乙走完全程需要时间,此时的时间应加上乙先前迟出发的 20分,即可求出答案.
【解答】 解:因为甲 60分走完全程 4千米,所以甲的速度是 4千米 /时,
由图中看出两人在走了 2千米时相遇,那么甲此时用了 0.5小时,则乙用了(0.5﹣ )小时,
所以乙的速度为:2÷=12,所以乙走完全程需要时间为:4÷12=(时) =20分,此时的时间应加上 乙先前迟出发的 20分,现在的时间为 8点 40.
故选 C .
【点评】 在做题过程中应根据实际情况和具体数据进行分析.本题应注意乙用的时间和具体时间之 间的关联.
二、填空题(共 10小题,每小题 3分,满分 30分)
11.将 1300000用科学记数法表示为 6 .
【考点】 科学记数法 — 表示较大的数.
【分析】 科学记数法的表示形式为 a ×10n 的形式,其中 1≤ |a|<10, n="" 为整数.确定="" n="" 的值时,要看把="" 原数变成="" a="" 时,小数点移动了多少位,="" n="" 的绝对值与小数点移动的位数相同.当原数绝对值="">1时, n 是正数;当原数的绝对值<1时, n="">
【解答】 解:将 1300000用科学记数法表示为:1.3×106.
故答案为:1.3×106.
【点评】 此题考查科学记数法的表示方法.科学记数法的表示形式为 a ×10n 的形式,其中 1≤ |a|<10, n="" 为整数,表示时关键要正确确定="" a="" 的值以及="" n="">
12.在函数 y=中,自变量 x 的取值范围是 x 2
【考点】 函数自变量的取值范围.
【分析】 根据分式有意义,分母不等于 0列式计算即可得解.
【解答】 解:由题意得, x+2≠ 0,
解得 x ≠ ﹣ 2.
故答案为:x ≠ ﹣ 2.
【点评】 本题考查了函数自变量的范围,一般从三个方面考虑:
(1)当函数表达式是整式时,自变量可取全体实数;
(2)当函数表达式是分式时,考虑分式的分母不能为 0;
(3)当函数表达式是二次根式时,被开方数非负.
13.计算 =
.
【考点】
二次根式的加减法.
【分析】 首先把
和
化成最简二次根式,再合并同类二次根式即可.
【解答】 解:
﹣ =
﹣ =3
﹣ 2 =.
故答案为:
. 【点评】 此题主要考查了二次根式的加减,关键是掌握二次根式相加减,先把各个二次根式化成最 简二次根式,再把被开方数相同的二次根式进行合并,合并方法为系数相加减,根式不变.
14.把多项式 2x 2﹣ 8分解因式得: 2(x+2)(x ﹣ 2) .
【考点】 提公因式法与公式法的综合运用.
【分析】 首先提公因式 2,然后利用平方差公式分解.
【解答】 解:2x 2﹣ 8=2(x 2﹣ 4) =2(x+2)(x ﹣ 2).
故答案是:2(x+2)(x ﹣ 2).
【点评】 本题考查了用提公因式法和公式法进行因式分解,一个多项式有公因式首先提取公因式, 然后再用其他方法进行因式分解,同时因式分解要彻底,直到不能分解为止.
15.一个扇形的圆心角为 120°,弧长为 6π,则此扇形的半径为 9 .
【考点】 弧长的计算.
【分析】 根据弧长公式 l=
,可得 r=,再将数据代入计算即可.
【解答】 解:∵ l=
, ∴ r===9. 故答案为:9.
【点评】 本题考查了弧长的计算,解答本题的关键是掌握弧长公式:l=
(弧长为 l ,圆心角度
数为 n ,圆的半径为 r ).
16.不等式组 的解集是
x
2
【考点】 解一元一次不等式组.
【专题】 计算题.
【分析】 分别解两个不等式得到 x >和 x <>
【解答】 解:,
解 ① 得 x >,
解 ② 得 x <>
所以不等式组的解集为
故答案为
【点评】 本题考查了解一元一次不等式组:求不等式组的解集的过程叫解不等式组.解一元一次不 等式组时,一般先求出其中各不等式的解集,再求出这些解集的公共部分,利用数轴可以直观地表 示不等式组的解集.解集的规律:同大取大;同小取小;大小小大中间找;大大小小找不到.
17.布袋中装有 3个红球和 6个白球,它们除颜色外其他都相同,如果从布袋里随机摸出一个球, 那么所摸到的球恰好为红球的概率是
.
【考点】
概率公式.
【专题】 常规题型.
【分析】 根据概率公式,求摸到红球的概率,即用红球除以小球总个数即可得出得到红球的概率.
【解答】 解:∵一个布袋里装有 3个红球和 6个白球,
∴摸出一个球摸到红球的概率为:
=. 故答案为:.
【点评】 此题主要考查了概率公式的应用,由已知求出小球总个数再利用概率公式求出是解决问题 的关键.
18.某公司 2月份的利润为 160万元, 4月份的利润 250万元,则平均每月的增长率为 25%
【考点】 一元二次方程的应用.
【专题】 增长率问题.
【分析】 设平均每月的增长率是 x ,根据 2月份的利润为 160万元, 4月份的利润 250万元,可列方 程求解.
【解答】 解:设平均每月的增长率是 x ,根据题意得
160(1+x) 2=250,
解得 x=25%或 x=﹣ 225%(舍去).
答:平均每月的增长率是 25%.
故答案为:25%.
【点评】 本题考查了一元二次方程的实际应用﹣﹣增长率问题, 若设变化前的量为 a , 变化后的量为 b ,增长率为 x ,则经过两次变化后的数量关系为 a (1±x ) 2=b(当增长时中间的 “±” 号选 “ +” ,当降低 时中间的 “±” 号选 “ ﹣ ” ).
19.等腰三角形的腰长为 5,一腰上的高为 3,则这个等腰三角形底边的长为 3
.
【考点】
勾股定理;等腰三角形的性质.
【分析】 此题要分两种情况进行讨论:(1)当等腰三角形的顶角是钝角时,腰上的高在三角形的外 部,先在 Rt △ ACO 中由勾股定理求出 AO=4,于是 OB=AB+AO=9,然后在 Rt △ BCO 中利用勾股定 理即可求出 BC 即可;
(2)当等腰三角形的顶角是锐角时,腰上的高在三角形的内部,在 Rt △ ACO 中由勾股定理求出 AD=4,于是 DB=AB﹣ AD=1,然后在 Rt △ BCD 中利用勾股定理求出 BC 即可.
【解答】 解:分两种情况:
(1)顶角是钝角时,如图 1所示:
在 Rt △ ACO 中,由勾股定理,得 AO 2=AC2﹣ OC 2=52﹣ 32=16,
∴ AO=4,
OB=AB+AO=5+4=9,
在 Rt △ BCO 中,由勾股定理,得 BC 2=OB2+OC2=92+32=90,
∴ BC==3; (2)顶角是锐角时,如图 2所示:
在 Rt △ ACD 中,由勾股定理,得 AD 2=AC2﹣ DC 2=52﹣ 32=16,
∴ AD=4,
DB=AB﹣ AD=5﹣ 4=1.
在 Rt △ BCD 中,由勾股定理,得 BC 2=DB2+DC2=12+32=10,
∴ BC=;
综上可知,这个等腰三角形的底的长度为 3
或 . 故答案为:3或 .
【点评】 本题考查了勾股定理及等腰三角形的性质,难度适中,分情况讨论是解题的关键.
20. 如图,
AC 是四边形 ABCD 的对角线, ∠ B=90°, ∠ ADC=∠ ACB+45°, BC=AB+, 若 AC=CD,
则边 AD 的长为
.
【考点】 正方形的判定与性质;勾股定理.
【分析】 作∠ DCM=∠ ACB ,并过 D 作 DH ⊥ CM 于 H ,延长 HD 交 BA 延长线于 K ,由 AAS 证明 △ ABC ≌△ DHC ,得出 BC=HC, AB=DH,证出四边形 BCKH 是正方形,得出∠ K=90°, BK=HK, 由已知条件得出 AK=DK=BC﹣ AB=, △ ADK 是等腰直角三角形,由勾股定理求出 AD 即可.
【解答】 解:作∠ DCM=∠ ACB , 并过 D 作 DH ⊥ CM 于 H , 延长 HD 交 BA 延长线于 K , 如图所示:
设∠ DCM=∠ ACB=x,
∵ AC=AD,
∴∠ DAC=∠ ADC=x+45°,
∴∠ ACD=180°﹣ 2(x+45°) =90°﹣ 2x ,
∴∠ BCH=90°,
在 △ ABC 和 △ DHC 中,
,
∴△ ABC ≌△ DHC (AAS ),
∴ BC=HC, AB=DH,
∴四边形 BCKH 是正方形,
∴∠ K=90°, BK=HK,
∴ AK=DK=BC﹣ AB=,
∴△ ADK 是等腰直角三角形,
∴ AD=
=.
故答案为:.
【点评】 本题考查了全等三角形的判定与性质、正方形的判定与性质、勾股定理等知识;本题综合 性强,有一定难度,通过作辅助线证明三角形全等是解决问题的关键.
三、解答题(共 7小题,满分 60分)
21.先化简,再求代数式 的值,其中 a=tan60°﹣ 6sin30°.
【考点】 分式的化简求值;特殊角的三角函数值.
【分析】 先根据分式混合运算的法则把原式进行化简,再求出 a 的值代入进行计算即可.
【解答】 解:原式 =
﹣ ? =
﹣ =,
∵ a=tan60°﹣ 6sin30°=﹣ 6×=
﹣ 3, ∴原式 ==
. 【点评】 本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.
22.如图,在每个小正方形的边长均为 1的方格纸中,线段 AB 的端点 A 、 B 均在小正方形的顶点 上.
(1)在方格纸中画出以 AB 为一条直角边的等腰直角 △ ABC ,顶点 C 在小正方形的顶点上;
(2)在方格纸中画出 △ ABC 的中线 BD ,将线段 DC 绕点 C 顺时针旋转 90°得到线段 CD ′ ,画出旋 转后的线段 CD ′ ,连接 BD ′ ,直接写出四边形 BDCD ′ 的面积.
【考点】 作图 -旋转变换.
【分析】 (1)直接利用等腰直角三角形的性质得出 C 点位置;
(2)直接利用三角形中线的定义以及结合网格直接得出四边形 BDCD ′ 的面积.
【解答】 解:(1)如图所示:△ ABC 即为所求;
(2)如图所示:CD ′ 即为所求,
四边形 BDCD ′ 的面积为:×=10.
【点评】 此题主要考查了旋转变换以及等腰直角三角形的性质,正确得出对应点位置是解题关键.
23.今年 3月 5日,某中学组织全体学生参加了 “ 走出校门,服务社会 ” 的活动,为了解九年级学生 参加活动情况,从九年级学生中随机抽取部分学生进行调查,统计了该天他们打扫街道,去敬老院 服务和到社区文艺演出的人数,并绘制了如下不完整的条形统计图和扇形统计图,其中到社区文艺 演出的人数占所调查的九年级学生人数的 ,请根据两幅统计图中的信息,回答下列问题: (1)本次成抽样调查共抽取了多少名九年级学生?
(2)补全条形统计图;
(3)若该中学九年级共有 400名学生,请你估计该中学九年级去敬老院的学生有多少名?
【考点】 条形统计图;用样本估计总体;扇形统计图.
【分析】 (1) 先根据条形图知到社区文艺演出的人数为 15人, 再由扇形统计图知占抽取总人数的 ,
两者相除即可求解;
(2)求出去敬老院服务的学生有多少人,即可补全条形统计图;
(3)用总人数乘以该年级去敬老院的人数所占的百分比即可.
【解答】 解:(Ⅰ)由题意,可得抽取的部分同学的人数为:15÷
=50(人);
(2)去敬老院服务的学生有:50﹣ 25﹣ 15=10(人).条形统计图补充如下:
(3)根据题意得:
400×=80(人)
答:估计该中学九年级去敬老院的学生有 80人.
【点评】 本题考查的是条形统计图和扇形统计图的综合运用,读懂统计图,从不同的统计图中得到 必要的信息是解决问题的关键.条形统计图能清楚地表示出每个项目的数据;扇形统计图直接反映 部分占总体的百分比大小.也考查了用样本估计总体的思想.
24.如图 1,正方形 ABCD 中,点 E 是边 BC 延长线上一点,连接 DE ,过点 B 作 BF ⊥ DE ,垂足为 点 F , BF 与 CD 相交于点 G .
(1)求证:△ BCG ≌△ DCE ;
(2)如图 2,连接 BD ,若 BE=4, DG=2,求 tan ∠ DBG 的值.
【考点】 正方形的性质;全等三角形的判定与性质;勾股定理.
【分析】 (1)只要证明∠ CBG=∠ CDE ,即可用 ASA 证明 △ BCG ≌△ DCE .
(2)利用勾股定理分别在 RT △ DHG , RT △ BHG 中,求出 BH , HG 即可解决.
【解答】 (1)证明:∵四边形 ABCD 是正方形,
∴∠ BCG=∠ DCE=90°, BC=CD,
∵ BF ⊥ DE ,
∴∠ DFG=∠ BCG=90°,
∵∠ BGC=∠ DGF ,
∴∠ CBG=∠ CDE .
在 △ BCG 和 △ DCE 中,
,
∴△ BCG ≌△ DCE ,
(2)解:∵△ BCG ≌△ DCE ,
∴ CG=CE,
∵ BE=BC+CE=4
, DG=CD﹣ CG=2, ∴ BC=CD=3, CG=CE=
, 在 RT △ BDC 中,∵∠ BCD=90°,
∴ BD===6,
过点 G 作 GH ⊥ BD 垂足为 H ,
∵∠ DHG=45°,∠ DHG=90°, DG=2
,
∴
=, ∴ DH=2,
∴ GH=DH=2,
∵ BD=BH﹣ DH ,
∴ BH=6﹣ 2=4,
在 RT △ BHG 中,∵∠ BHG=90°,
∴ tan ∠ DBG=, ∴ tan ∠ DBG=.
【点评】 本题考查正方形的性质、全等三角形的判定和性质、勾股定理等知识,利用线段和差关系 求出线段 BC , CG 是解题的关键.
25. 植树节期间, 某单位欲购进 A 、 B 两种树苗, 若购进 A 种树苗 3棵, B 种树苗 5颗, 需 2100元, 若购进 A 种树苗 4颗, B 种树苗 10颗,需 3800元.
(1)求购进 A 、 B 两种树苗的单价;
(2) 若该单位准备用不多于 8000元的钱购进这两种树苗共 30棵, 求 A 种树苗至少需购进多少棵?
【考点】 一元一次不等式的应用;二元一次方程组的应用.
【分析】 (1)设 B 树苗的单价为 x 元,则 A 树苗的单价为 y 元.则由等量关系列出方程组解答即 可;
(2)设购买 A 种树苗 a 棵,则 B 种树苗为(30﹣ a )棵,然后根据总费用和两种树的棵数关系列出 不等式解答即可.
【解答】 解:设 B 树苗的单价为 x 元,则 A 树苗的单价为 y 元,可得:,
解得:,
答:B 树苗的单价为 300元, A 树苗的单价为 200元;
(2)设购买 A 种树苗 a 棵,则 B 种树苗为(30﹣ a )棵,
可得:200a+300(30﹣ a ) ≤ 8000,
解得:a ≥ 10,
答:A 种树苗至少需购进 10棵.
【点评】 本题考查了方程组的应用,一元一次不等式组应用,解决问题的关键是读懂题意,找到关 键描述语,进而找到所求的量的等量关系和不等关系.
26.如图 1, BC 是⊙ O 的直径,点 A 在⊙ O 上,点 D 在 CA 的延长线上, DE ⊥ BC ,垂足为点 E , DE 与⊙ O 相交于点 H ,与 AB 相交于点 l ,过点 A 作⊙ O 的切线 AF ,与 DE 相交于点 F . (1)求证:∠ DAF=∠ ABO ;
(2)当 AB=AD时,求证:BC=2AF;
(3)如图 2,在(2)的条件下,延长 FA , BC 相交于点 G ,若 tan ∠ DAF=, EH=2
,求线段
CG 的长.
【考点】 圆的综合题;全等三角形的判定与性质;勾股定理;相似三角形的判定与性质;锐角三角 函数的定义.
【专题】 综合题.
【分析】 (1)连接 AO ,如图 1,由 OA=OB可得∠ OAB=∠ OBA ,要证∠ DAF=∠ ABO ,只需证 ∠ DAF=∠ BAO ,只需证∠ FAO=∠ DAB=90°即可;
(2)由于 BC=2OA,要证 BC=2AF,只需证 OA=AF,只需证 △ AFD ≌△ AOB 即可;
(3)过点 A 作 AN ⊥ BC 于 N ,连接 OH , OA ,如图 2,易得 BE=2IE, DE=2EC, DI=2AF=BC,从 而可得 EC=3IE=BE .设 BE=2x,则有 EC=3x, BC=5x, HO=BO=
, EO=.在 Rt △ HEO
中运用
勾股定理可求出 x .利用三角函数可得 BN=2AN=4NC,则有 BC=5NC=10,从而可求出 NC 、 ON , 易证 △ AON ∽△ GOA ,根据相似三角形的性质可求出 OG ,从而可求出 CG .
【解答】 解:(1)连接 AO ,如图 1.
∵ AF 与⊙ O 相切于点 A ,
∴ OA ⊥ AF ,即∠ FAO=90°.
∵ BC 是⊙ O 的直径,
∴∠ BAC=90°,
∴∠ DAB=90°,
∴∠ FAO=∠ DAB=90°,
∴∠ DAF=∠ BAO .
∵ OA=OB,
∴∠ OAB=∠ OBA ,
∴∠ DAF=∠ ABO ;
(2)∵ DE ⊥ BC ,∴∠ DEB=90°,
∴∠ DTB=90°+∠ ABO .
∵∠ DTB=90°+∠ D ,
∴∠ D=∠ ABO .
在 △ AFD 和 △ AOB 中,
,
∴△ AFD ≌△ AOB ,
∴ AF=AO,
∴ BC=2OA=2AF;
(3)过点 A 作 AN ⊥ BC 于 N ,连接 OH , OA ,如图 2.
∵∠ D=∠ B=∠ BAO=∠ DAF , tan ∠ DAF=,
∴ tanB==, tanD==,
∴ BE=2IE, DE=2EC.
又∵∠ DIA+∠ D=∠ DAF+∠ FAI=90°,
∴∠ FIA=∠ FAI ,
∴ FI=FA,
∴ DI=2AF=BC,
∴ DE ﹣ IE=BE+EC,
∴ 2EC ﹣ IE=2IE+EC,
∴ EC=3IE=BE .
设 BE=2x,则有 EC=3x, BC=5x, HO=BO=
, EO=.
在 Rt △ HEO 中,根据勾股定理可得
() 2+(2) 2=() 2, 解得 x=2(舍负).
∵ AN ⊥ BC ,∠ BAC=90°,
∴∠ NAC=∠ ABC ,
∴ tan ∠ NAC==, tan ∠ ABC==,
∴ BN=2AN=4NC,
∴ BC=5NC=10,
∴ NC=2, ON=5﹣ 2=3.
∵∠ AON=∠ GOA ,∠ ANO=∠ OAG=90°,
∴△ AON ∽△ GOA ,
∴
=, ∴ =,
∴ OG=,
∴ CG=OG﹣ OC=
.
【点评】 本题主要考查了圆的切线的性质、圆周角定理、全等三角形的判定与性质、相似三角形的 判定与性质、三角函数的定义、等腰三角形的判定与性质、勾股定理等知识,有一定的综合性,用 含有 x 的代数式表示出 OE 、 OH ,并在 Rt △ HEO 中运用勾股定理是解决第(3)小题的关键.
27.如图 1,在平面直角坐标系中,点 O 为坐标原点,抛物线 y=x2+bx﹣ 3与 x 轴相交于点 A (﹣ 3, 0)和点 B ,与 y 轴相交于点 C .
(1)求抛物线的解析式;
(2) 如图 2, 直线 y=kx+3k经过点 A , 与 y 轴正半轴相交于点 D , 点 P 为第三象限内抛物线上一点, 连接 PD 绕点 P 逆时针旋转,与线段 AD 相交于点 E ,且∠ EPD=2∠ PDC ,若∠ AEP+∠ ADP=90°, 求点 D 的坐标;
(3)如图 3,在(2)的条件下,过点 E 作 EF ⊥ PD ,垂足为点 G , EF 与 y 轴相交于点 F ,连接 PF , 若 sin ∠ PFC=,求 PF 的长.
【考点】 二次函数综合题.
【专题】 综合题.
【分析】 (1)直接把 A 点坐标代入 y=x2+bx﹣ 3求出 b 的值即可得到抛物线解析式为 y=x2+2x﹣ 3;
(2)如图 2,由三角形外角性质得∠ AEP=∠ 2+∠ 3,加上∠ 3=2∠ 1,则∠ AEP=∠ 2+2∠ 1,再利用 ∠ AEP+∠ 2=90°可∠ 1+∠ 2=45°,于是可判断 △ AOD 为等腰直角三角形,则 OD=OA=2,由此得到 D 点坐标为(0, 2);
(3) 过 D 作 DH ⊥ y 轴交 PE 的延长线于 H , 作 PM ⊥ DH 于 M , PN ⊥ y 轴于 N , 如图 3, 利用 PM ∥ DN
得到∠ PDC=∠ DPM ,加上∠ EPD=2∠ PDC ,则∠ HPM=∠ DPM ,于是根据等腰三角形的性质可得 MH=MD,接着判断四边形 PNDM 为矩形得到 MD=PN,则 DH=2PN,然后证明 △ DEH ≌△ DEF 得 到 DH=DF,所以 DF=2MD=2PN;再在 Rt △ PFN 中利用正弦定义可得到 PF=3PN,利用勾股定理得 FN=PN ,设 P 点坐标为(t , t 2+2t﹣ 3),则 DF=﹣ 2t , FN=﹣ 2
t ,于是可表示出 ON=DF+FN﹣ OD=﹣ 2t ﹣ 2t ﹣ 3,所以﹣ 2t ﹣ 2
t ﹣ 3=﹣(t 2+2t﹣ 3),解方程得到得 t 1=﹣ , t 2=3(舍 去),所以 PF=3PN=3
. 【解答】 解:(1)把 A (﹣ 3, 0)代入 y=x2+bx﹣ 3得 9﹣ 3b ﹣ 3=0,解得 b=2,
所以抛物线解析式为 y=x2+2x﹣ 3;
(2)如图 2,∵∠ AEP=∠ 2+∠ 3,
而∠ 3=2∠ 1,
∴∠ AEP=∠ 2+2∠ 1,
∵∠ AEP+∠ 2=90°,
∴∠ 2+2∠ 1+∠ 2=90°,
∴∠ 1+∠ 2=45°,即∠ ADO=45°,
∴△ AOD 为等腰直角三角形,
∴ OD=OA=2,
∴ D 点坐标为(0, 2);
(3)过 D 作 DH ⊥ y 轴交 PE 的延长线于 H ,作 PM ⊥ DH 于 M , PN ⊥ y 轴于 N ,如图 3, ∵ PM ∥ DN ,
∴∠ PDC=∠ DPM ,
∵∠ EPD=2∠ PDC ,
∴∠ HPM=∠ DPM ,
而 PM ⊥ DH ,
∴ MH=MD,
易得四边形 PNDM 为矩形,
∴ MD=PN,
∴ DH=2PN,
∵ EF ⊥ PD ,
∴∠ GDF+∠ DFG=90°,
而∠ PHD+∠ HPM=90°,
∴∠ DFG=∠ PHM ,
∵∠ ADF=45°,
∴∠ HDE=45°,
在 △ DEH 和 △ DEF 中
,
∴△ DEH ≌△ DEF ,
∴ DH=DF,
∴ DF=2MD=2PN,
在 Rt △ PFN 中,∵ sin ∠ PFC=
=, ∴ PF=3PN,
∴ FN===2PN ,
设 P 点坐标为(t , t 2+2t﹣ 3),则 DF=﹣ 2t , FN=﹣ 2
t , ∴ ON=DF+FN﹣ OD=﹣ 2t ﹣ 2
t ﹣ 3, ∴﹣ 2t ﹣ 2
t ﹣ 3=﹣(t 2+2t﹣ 3),
整理得 t 1=﹣ , t 2=3
(舍去), ∴ PF=3PN=﹣ 3t=3
.
【点评】 本题考查了二次函数的综合题:熟练掌握二次函数图象上点的坐标特征和等腰三角形的性 质;会应用三角形全等证明线段相等;理解锐角三角函数的定义.
范文三：2016南岗区中考物理二模试题和答案
黑龙江省哈尔滨市南岗区 2016年中考物理复习情况调研试题(二)
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5
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物理参考答案
一、选择题
16.C 17.C 18.A 19.C 20.B 21.A 22.C 23.D 24.A 25.C 26.A 27.D 三、非选择题
36. 用电器 导线
37. 增大 增大
38. 电磁波 超声波
39. 2.5 5.5
40. 内 做功
41. 惯性 减小越快
42. 8.4×106 20
43. 减弱 2ρ/5
44.
45. 0.9 5.4
46. 略
47. 略
48. (1)①将蜡烛、眼镜、凸透镜、光屏依次放在同一直线上
②使它们的中心在同一高度上
(2)会聚 远视眼
49. (1)电流产生的热量可能跟通电时间有关
电水壶烧水时间越长,水温升高越大
(2)①略
②在电流、通电时间相同时,电阻越大,电流产生的热量越多
③在控制电流、通电时间相同时,改变电阻,通过比较煤油升高的温度即可
50. (1)①探究液体压强跟深度的关系
②同种液体,压强随深度的增加而增大
(2)① b. 将微小压强计的探头分别放在水和盐水中的同一深度,比较 U 型管液面的高度差 C.重复步骤 b ,在不同深度处多做几次实验
②水和盐水的密度相差不大,使同一深度液体内部压强的差异不明显
51. (1)额外功计算错误,没有计算人克服自重做功
计算机械效率没有公式,缺少计算依据
(2) η=84.2%
(3)在 G 、 G 动相同时, G 桶>G 袋,∴ η桶<>
8
范文四：2011南岗二模
2011南二模岗岗岗
21. Boys and girls, you must remember, “A house faster after a rest” Every time when you have studied for_____ long time, please stop to have a good rest.
A a B. the C. an
th22. – The 26 World Universiade will be held in ShenZhen in August. Not only LiuMing but also WangLei and Lucy _____to be a volunteer. What’s your idea, Mary?
--Oh, really? May I join them, too?
A wants B. want C. wanting
23. -- If it ______tomorrow, what about going to Children’s Park together?
--Good idea!
A isn’t rain B. won’t rain C. doesn’t rain
24. –Where is Mr. Green these days? I haven’t seen him for nearly two weeks.--Oh, he_____ Shanghai for a week and he will be back to Harbin in three days.A has been to B. has gone to C. has been in
25. –Would you like to come over to my home to celebrate my grandfather’s ____ birthday this weekend, Jim?
---Certainly! See you then.
A ninety B. ninetieth C. ninetieth
26. –It is three years since the earthquake happened in WenChuan.
---Whenever I think of it, I feel very sad. Due to the fact that it happened_____ the afternoon of thMay 12 , 2008, many students died from it.
A in B. at C. on
27. As a student in Grade Nine, I’m too busy _____ anything else except studying.---However, I think we must spend some time dong sports in order to keep healthy.A to do B. doing C. do
28. No matter when you meet the new word that you don’t understand in the reading, don’t ____ the word at once, think it over and try to guess the meaning according to the content of an article.A look at B. look after c. look up
29. –Could you tell me how to learn English well?
----You must pay more attention to listening and speaking. I find ____ impossible to learn English well if you don’t care about these two skills.
A that B. it C. this
30. --_____ is it from your school to your home?
---It’s about ten minutes’ walk. So I go to school on foot every day.
A How long B. how soon C. How far
31. We will take the High School Entrance Examination in ____ two months. Please keep studying hard, don’t lose heart no matter how difficult the problems are.
A over than B. less than C. fewer than
32. Number ____ is considered as the most unlucky number in western countries. If it comes along with Friday, people think it will bring bad luck. Besides, most of the hotel rooms do not have a room with that number.
A 13 B. 14 C.15
33. Nowadays, protecting the environment is becoming more and more important in our daily life. In order to live a low-carbon life, what shouldn’t we do?
?Go to school on foot everyday if we don’t live far from our school
?Turn off the lights, the TV and the fans when leaving the room.
?Use plastic bags as much as possible.
?Never make full use of paper, never use two sides of the paper.
?Always use one-off(一次性) chopsticks.
A,??? B. C. ??????
34. More and more women athletes have taken part in the Olympic Games since 1988. The number of men athletes was nearly _____ times larger than that of women athletes at the Olympic Games in 1988.
A. 2 B 3 C.4
35 Which word of the following has a different stress from the others?A.Italy B. friendship C. include
范文五：南岗二模数学答案
2014年初中升学考试调研测试(二)
数学试卷参考答案与评分标准
二、 (每小题 3分,共计 30分)
解:
4....... .......... .......... .......... .......... .......... .......... .......... .......... 1
1
1) 2() 1(12
1) 1() 1)(1(21111) 1211(
2'
-=----=
---=+???
????+---+=+÷---+a a a a a a a a a a a a a a a 因为 a =tan60°+2sin 30°=1. .......... .......... .......... .......... .......... .......... 12
1
2'+=?
+ 所以 1......... .......... .......... .......... .......... 31
111111) 1211(
2'=-+=-=+÷---+a a a a a
22. (本题满分 6分 )
(1)画正确 .................................................................................................................................. 3' (2)画正确 .................................................................................................................................. 3' 23. (本题满分 6分 )
(1) 1.... .......... .......... .......... .......... .......... .......... .......... .......... ).........
(200%2550'=÷人 到 B 景区的人数 1. .......... .......... .......... .......... ).........
(5050107020200'=----人 图形符合要求 ........................................................................................................................ 1'
(2) 2... .......... .......... .......... .......... .......... .......... .......... .......... )......... (350200
70
1000'=?
人 估计到 C 景区“一日游”的学生人数为 350人 ................................................................ 1'
24. (本题满分 6分 )
(1)在 中 ABC ? 过点 B 作 AC 的垂线 , 垂足为 D , 依题意可得 60, 45, 45=?=∠?=∠AB DBA DAB
2........ .......... .......... .......... .......... .......... .......... 22
2
6045sin '=?
=??==AB BD AD 轮船行驶到灯塔 B 的西北方向点 D 所用的时间为 22
3
20230=
÷(小时) .................... 1' (2)在 BDC ?中, 2
1
60cos 2cos , 90, 601545=?===
∠?=∠?=?+?=∠BC BC BD DBC BDC DBC , 3....... .......... .......... .......... .......... .......... .......... .......... .......... .......... )......... (2'=∴海里 BC 答:灯塔 B 到 C 处的距离是 602 海里 . 25. (本题满分 8分)
(1)连接 OD, 在⊙ O 中, 1..... ..........
, , , '∠=∠∴=∠=∠=CED CDE CE CD ODB B OD OB 3. . . . . .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . , , 90, .
9090180, 90, '∴⊥∴?=∠+∠=∠+∠∴∠=∠?=?-?=∠+∠∴?=∠∴⊥?的切线 是圆 中, 在 O CD CD OD OEB B CDE ODE OEB CED OEB B BOE AB OC BEO (2)连接 AD , 在 ABD ?中,∵ AB 是直径, AB
DB
ABD BE OB B BOE ADB =∠==
∠∠=?=∠∴cos cos , 90 4.......... .......... .......... .......... .......... 24
119
2416912, 24169, 131213
'=-=∴=∴=∴DE BE BE
26. (本题满分 8分)
(1)该商店第一批购进冰刀 x 双,则第二批购进 x 2双 . 依题意可得
2... .......... .......... .......... .......... .......... .......... .......... .......... 204800
210800'=-x
x 解得 1..... .......... .......... .......... 30, 02, 0, 30, 30'=∴≠≠==是原方程的解 时 当 x x x x x ) (603022双 =?=x ,该商店第二批购进这种品牌的冰刀 60双 ........................................ 1' (2)设每双冰刀的售价为 y 元,依题意可得
2. . . . . . . . . . . . . . . . . . . . . . . . . %.. . . . . . . . 20%10010800
480010800
4800) 6030('≥?+--+y
解得 , 208≥y 所以每双冰刀售价至少是 208元 .................................................................... 2' 27. (本题满分 10分)
(1)如图 1,在四边形 ABCO 中,
A O C BAO ABC x BC BAO x BA ∠=∠=?=?-?=∠∴?=∠∴⊥9090180//. 90轴, 轴, ,
∴四边形 ABCO 是矩形, 34, 4====∴OA BC OC AB , 点 C 的坐标为 ) 4, 0(, 依题意可得
???
????+?+?=+?+?=c b c b 0) 0(3144) 34(3
1422
解得 ?????=-=4
334c b
所求抛物线的解析式为 43
34312+-=
x x y ............................................ 2' (2) 如图 1,过 Q 作 x 轴垂线,垂足为 K , QH ⊥ AB ,垂足为 H. 在 ABO R t ?中, ?=∠∴?====
∠60, 60tan 4
4tan ABO AB OA ABO . 1.. .......... .......... .......... .......... .......... .......... ..........
12060180, //'?=?-?=∠∴QPB OB PQ , PB=PQ=2t, ∴?=∠?=?
-?=
∠=∠∴, 90, 302
120180BHQ PQB PBQ PH=t, QH=3t ,
延长 HQ 交 y 轴于点 S , ∴?=∠=∠=∠, 90AOS AHS HAO 四边形 AHSO 是矩形 t HQ AK OA OK t BH AH OS QK 434, 344-=-=-=-=-===∴
Q (4-t , 4-3t )代入抛物线解析式,解得 t 1=1, t 2=0(舍) ......................................... 2' (3) 如图 2,在 ABE ?中,
33
4
, 330tan 4tan , 30, 90=∴=?===
∠?=∠?=∠AE AE AB AE ABE ABE BAE 3
8, =
∴-=OE AE OA OE ,E (38, 0) ,.......................................................................... 1'
如图 3,取 OE 的中点 M ,连接 MG 、 CM , MG=
21OE=34, CM=3
8, CG+GM≥CM ,当 G 在 CM 上时, CG 最短 ................................................................................................................................................ 1' 如图 4,作 GN ⊥ y 轴, GR ⊥ x 轴,
3
==CN NG OC OM , 设 GN=k ,则 CN=3k, RG=ON=4-3k, G (k , 4-3k ) , MR=
3
4-3k, 由勾股定理得, 图 1
222MG RG MR =+, ()22
2343334334k k -+???
? ??-=???? ??,解得 k 1=32
, k 2=2(舍 )............................ 2' G (
32, 2) , m=3
8
, G 点不在抛物线上 .......................................................................................................... 1'
28.(本题满分 10分 ) (1) 方法 1:如图 1
过 A 作 DF 的平行线交 BC 于 K ,∵ AK ∥ DF ,∴ BD
BK
BF AB =, ................................................... 1' ∵ AK ∥ DE ,∴
CK
CD
AC CE =, ............................................................................................................... 1' ∵∠ BDA =∠ CDE ,∴∠ AKC=∠ ADB ,∵ AB=AC,∴∠ B=∠ C ,∴△ ABD ≌△ ACK , .......... 2'
∴ BD=CK, BK=CD,∴ CK CD BD BK =,∴ , , , AC AB AC AB CE BF AC
CE
BF AB =?=?∴= ∴ BF×CE =AB 2........................................................................................................................................ 1'
方法 2:如图 2
∵ AB=AC, ∴∠ B =∠ C , ∵∠ ADB =∠ FDC , ∴∠ BDF =∠ CDA , ∴△ BDF ∽△ CDA ,
∴
CD
BD
AC BF =, ...................................................................................................................................................... 2' ∵∠ B =∠ C , ∠ ADB =∠ FDC , ∴△ ABD ∽△ ECD , ∴ CD
BD
CE AB =, ............................................................ 2' ∴ CE
AB
AC BF =,∴ BF×CE =AB×AC=AB2............................................................................................................ 1'
B C 图
1
B 图 2
图 2 图 3
图 4
(2) ∵∠ BGC =∠ BCH ,∠ GBC =∠ CBH ,∴△ GBC ∽△ CBH ,∴∠ BHC =∠ BCG , ........................... 1'
∵∠ FBC =∠ HCB ,∴△ BHC ∽△ FCB ,∴
BC CH =BF
BC
,∴ BC 2=CH×BF , .............................................. 1' 过点 A 作 BC 的垂线,垂足是 K , ?=∠120BAC
则 2
cos , 90, 2, 302120180=
==∠?=∠==?=?-?=∠=∠AB BC
AB BK ABK AKB BC CK BK ACB B ∴ BC 2=3AB2,由 (1)得 BF×CE =AB 2,∴ CH×BF=3BF×CE
∴ CH=3CE. ................................................................ 1'
①如图 3,当 H 在 AC 上时,
AB 、 CE 、 AH 这三条线段之间的数量关系:3CE+AH=AB....................................................................1' ②如图 4,当 H 在 CA 延长线上时,
(图 4)
